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Mathematics

1 answer:

poizon [28]3 years ago

4 0

Add all her expenses =2024.08

Then divide by 165=12.268

Go with choice 12.27

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The graph of the function

Anettt [7]

Answer:

D.The function is decreasing for all real values of x where x < 1.5

Step-by-step explanation:

The vertex is at x=1.5, so the function is decreasing on one side of that and increasing on the other. Any answer choice with some number other than 1.5 as the boundary of increasing/decreasing can be ignored.

Of course one descriptor (<em>increasing</em> or <em>decreasing</em>) is not applicable for any interval that includes the point where the slope changes sign.

The function is decreasing for all real values of x where x < 1.5.

4 0

3 years ago

Read 2 more answers

Which represents where f(x) = g(x)?

ANEK [815]

Answer:

f(2) = g(2) and f(0) = g(0)

Step-by-step explanation:

When x = x in f(x) and g(x), that means the two functions are equal.

7 0

2 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)