Answer:
The original concentration is "35 mg/ml".
Explanation:
According to the question,
The solution is diluted,
= 1:50
The initial volume,
V1 = 1 ml
Final concentration,
= 0.07 mg
then,
The final volume,
V2 = 500 ml
As we know,
⇒ 
or,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
0.0015 kilometers is for sure the answer!
Answer:
3.0002 moles
Explanation:
Data Given:
mass of NO₂ = 138.01 g
No. of moles NO₂ = ?
Solution
To find mass of sample mole formula will be used
mole formula
no. of mole = mass in grams / molar mass
Molar mass of NO₂ = 14 + 2(16)
Molar mass of NO₂ = 14 + 32 = 46 g/mol
Put values in above equation
no. of mole = 138.01 g / 46 g/mol
no. of mole = 3.0002 moles
no. of mole of NO₂ = 3.0002 moles
(of a river or road) follow a winding course
Answer:
gimme that chocky milk.....
Explanation:
