B.................................................
use x^2 when x=0 because the restriction for it is "use x if x is less than or equal to 1"
when x = 0, (0)^2 will make f(x) = 0
the graph of f(x) will just be a dot at 0
Answer:
translation 2 units left
; reflection across the y-axis
Step-by-step explanation:
The y-coordinates of the points do not change from the pre-image to the image. This means there is no translation down (this would add or subtract to the y-coordinates) and no reflection across the x-axis (this would negate the y-coordinates).
This leaves us with a translation 2 units left and a reflection across the y-axis.
The translation 2 units left adds 2 to the x-coordinates, and the reflection across the y-axis negates the x-coordinates. If we add 2 first, the coordinates would be (-4+2, 6) = (-2, 6); (-2+2, 2) = (0, 2); and (-6+2, 2) = (-4, 2).
Negating each of these would give us (2, 6); (0, 2); and (4, 2). These are the desired image coordinates.
Answer:
Below.
Step-by-step explanation:
Substitute x = 3 into each polynomial and see if the value of the polynomial is zero. If it is zero then x-3 is a factor.
Try number 1:
a(x) = x^3 - 2x^2 - 4x + 3
a(3) = 3^3 - 2(3)^2 - 4(3) + 3
= 27 - 2(9) - 12 + 3
= 27 - 18 - 12 + 3
= 9 - 18 - 9
= 27 - 27
= 0
So a(x) has (x-3) is a factor of a(x)
The other 3 polynomials are solved in the same way.
Answer:
A
Step-by-step explanation:
Please give brainliest
