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3 years ago

What is the measurement of these two angles A:106 B:102 C:13 D:95

Mathematics

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

A: 106°

Step-by-step explanation:

Assuming lines A and B are parallel, the two marked angles are corresponding, hence, congruent.

8x +2 = 14x -76

78 = 6x . . . . . . . . . . add 76-8x

13 = x . . . . . . . . . . . . divide by 6

The angle measures are then ...

8(13) +2 = 104 +2 = 106 . . . degrees

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A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.By what percentage is the grapefruit heav

shepuryov [24]

To solve this problem you must apply the proccedure shown below:
1. You have that a grapefruit is 8% heavier than an orange and an apple is 10% lighter than the orange. Therefore, let's give a value to the orange as following:
Orange=1 kg
2. Therefore, you have:
Grapefruit=1 kg+(0.08x1 kg)=1.08 kg
Apple=1 kg-(0.1x1 kg)=0.9 kg
3. Therefore, what percentage is the grapefruit heavier than the apple?
%=(0.9/1.08)100-100
%=16.66%
The answer is:16.66%

5 0

4 years ago

Which rule represents the table's values? y = 2x y=-2x y=-12% V = -2x + 1

hram777 [196]

Answer:

Therefore the required rule for the given table is

$y=-2x$

Step-by-step explanation:

Given :

Table values are

x y

6 -12

7 -14

8 -16

9 -18

10 -20

To Find :

The rule for above result = ?

Solution:

The Required Rule for the above Table is

$y=-2x$

For first case

Put x = 6 in the rule we get

$y=-2\times 6 =-12$ as shown in the table

For second case

Put x = 7 in the rule we get

$y=-2\times 7 =-14$ as shown in the table

For third case

Put x = 8 in the rule we get

$y=-2\times 8 =-16$ as shown in the table

For fourth case

Put x = 9 in the rule we get

$y=-2\times 9 =-18$ as shown in the table

For fifth case

Put x = 10 in the rule we get

$y=-2\times 10 =-20$ as shown in the table

Therefore the required rule for the given table is

$y=-2x$

7 0

4 years ago

For each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts. A large shipmen

Stella [2.4K]

Answer:

(a) The p-value of the test statistic should be 0.33.

(b) No, there is not sufficient evidence to reject the entire shipment.

Step-by-step explanation:

We are given that for each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts.

A quality control manager randomly selects 50 of the parts from the shipment and finds that 6 parts are defective.

Let p = proportion of defective parts among the current shipment.

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the defective parts in the shipment is at most 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the defective parts in the shipment is greater 10%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of parts that are defective among the current shipment = $\frac{6}{50}$ = 12%

n = sample of parts from the shipment = 50

So, test statistics = $\frac{0.12-0.10}{\sqrt{\frac{0.12(1-0.12)}{50} } }$

= 0.44

The value of z test statistics is 0.44.

(a) Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.44) = 1 - P(Z $\leq$ 0.44)

= 1 - 0.67003 = 0.3299 ≈ 0.33

(b) Since, the P-value of test statistics is more than the level of significance as 0.33 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the defective parts in the shipment is at most 10%.

4 0

3 years ago

Https://files-cdn.schoology.com/eff1043385e13ac014eaf6e69f84525b?content-type=app

Anarel [89]

Answer:

srry i need points

Step-by-step explanation:

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3 years ago

Which table shows x- and y-values for 3 points on the line graphed below?

postnew [5]

C. You are right on the question

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3 years ago