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2 years ago

Which angle is an x-intercept for the function y = cos(1/2x)

2 answers:

3 0

For the function
y = cos(1/2 x)
The x-intercept can be calculated by equating the function to zero and solving for x. So,
y = cos(1/2 x) = 0
1/2 x = arc cos 0
1/2 x = 90° +180°n
x =2 (90° +180°n)
x = 180° + 360°n
or converting to radians
x = (180° + 360° n)(π/180°)
x = π + 2π n
where n is any whole number

if n = 0
x = π

Therefore, the x-intercept is π or π+2π n

Alisiya [41]2 years ago

3 0

PLATO ANSWER: Pi (π)

Hope I helped, Have a great day!!!

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What might be the units that you write in the blanks that make this true?

Ilya [14]

Answer:

6.2 kilometres = 6200 meters

Step-by-step explanation:

6.2 kilometres is 1000 times less than 6200 meters

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3 years ago

Which pair of angles are congruent? A. 4 and 5 B. 1 and 7 C. 2 and 5 D. 6 and 8

erik [133]

Answer:

B: 4 and 5

Step-by-step explanation:

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2 years ago

Read 2 more answers

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

5 0

3 years ago

Will award brainliest to correct answer!

Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

$\angle \: ABP = \frac{180 - 80}{2} = 50 \degree$

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0

2 years ago

C=2pie r solve for r

S_A_V [24]

Answer:

r = C / (2pie)

Step-by-step explanation:

C = 2pie x r

divide both sides by 2pie to isolate r

C / (2pie) = r

r = C / (2pie)

8 0

3 years ago