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Alex777 [14]
3 years ago
12

3.309 in expanded word form

Mathematics
1 answer:
bezimeni [28]3 years ago
3 0
Three and three-hundred nine thousandths = 3.309
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Find the area of the following figure below
icang [17]
140
explanation: ......
6 0
3 years ago
Out of 600 seniors at a local high school, 60% went on the senior trip. At the hotel, one room was reserved for every 4 students
butalik [34]

Given:

Total number of senior students = 600

60% went on the senior trip.

One room was reserved for every 4 students.

To find:

The total number of reserved rooms.

Solution:

60% went on the senior trip from total 600 students. So, number of students who went on tripe is

600\times \dfrac{60}{100}=360

Now, one room was reserved for every 4 students. So,

\text{Required number of rooms}=\dfrac{\text{Number of students who went on tripe}}{\text{Number of students in room}}

\text{Required number of rooms}=\dfrac{360}{4}

\text{Required number of rooms}=90

Therefore, the required number of reserved rooms were 90.

4 0
3 years ago
3. Math test scores: 93, 86, 93, 85, 73 mean = median = mode(s) = range = © M. Tallman 2014 ww​
GalinKa [24]

Answer:

Mean = 86

Median = 86

Mode = 93

Range = 20

Step-by-step explanation:

Mean is the average of a set of numbers. To find the average, you add all the numbers together and divide the product by how many numbers are in the set so:

93 + 86 + 93 + 85 + 73 = 430

430/5 = 86

Median is the middle of a set of numbers.

First put the numbers in order of smallest to biggest

73, 85, 86, 93, 93.

The middle number is 86 so the median is 86.

A mode or modes are numbers that appear most frequently in a number of sets. They’re can be multiple modes.

The most frequent number is 93 so the mode is 93

Range is the difference of the biggest number and the smallest number. The biggest is 93 and the smallest is 73.

93 - 73 = 20

The range is 20

6 0
2 years ago
I just need the last one please
melisa1 [442]

Answer:

7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The equation 9 x 2 − 12 x + 4 = 0 9 x 2 − 12 x + 4 = 0 has how many different solutions?
Hatshy [7]

We have the equation:

9x^2-12x+4=0

so:

a=9\qquad b=-12\qquad c=4

and:

\Delta=b^2-4ac=(-12)^2-4\cdot9\cdot4=144-144=\boxed{0}

This equation has one solution.

5 0
3 years ago
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