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1 year ago

How many fourth-fifths are in eight

Mathematics

1 answer:

Elenna [48]1 year ago

7 0

Answer:

Step-by-step explanation:

8 ÷ 4/5 = 10

I hope this helps!!

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a bag contains 2 red marbles, 3 green marbles, and 2 black marbles what is the probability of drawing out a black marble

GuDViN [60]

Answer:

P (black) = 2/7

Step-by-step explanation:

We need to know the total amount of marbles.

2 red + 3 green + 2 black = 7 marbles

P ( black) = number of black marbles / total marbles

= 2 /7

8 0

2 years ago

Read 2 more answers

Please solve both, graph and show work. answer also has to be in y=mx+b format.

alexandr1967 [171]

2x-y=1
-2x -2x
-----------------
-y=-2x+1
Multiply by -1
y=2x-1

x+y=2
-x -x
------------
y= -x+2

8 0

3 years ago

What are the vertices of PQR?

andrew-mc [135]

Answer:

your answer is C

Step-by-step explanation:

vertices neither contain angle nor contain complement

6 0

2 years ago

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A 26-foot ladder is placed against a house and reaches the 24-foot roof. If you want to find the distance between the base of th

dedylja [7]

Answer:

b or the second one

Step-by-step explanation:

3 0

2 years ago

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For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

4 0

3 years ago