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3 years ago

Find perimeter of a regular Pentagon sides 3.3cm long

Mathematics

1 answer:

tatuchka [14]3 years ago

5 0

6.6 + 12.12 =18.18.

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Write an algebraic equation that relates the Profit to the Number of T-Shirts Sold. Use n to represent T-Shirts and p to represe

Simora [160]

Answer:

y= 3x -5

Step-by-step explanation:

since when x is 0, and y is -5, you know that the y intercept is -5.

look at the table

1x -5 = -2

x= 3

Boom.

LONG LIVE KOREA!

7 0

3 years ago

X 2 −3x−10=x, squared, minus, 3, x, minus, 10, equals

Andreyy89

Step-by-step explanation:

my brain couldn't comprehend can u write it down for me real quick like the way it's supposed to be written please

5 0

3 years ago

Find the limit. (If an answer does not exist, enter DNE.) lim ( (1/x)-(1/lxl)) x→0^+

jek_recluse [69]

Answer:

Step-by-step explanation:

The + on the zero means the limit as x approaches 0 from the right side

$\lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{|x|})\\ \lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{x})\\ \lim_{x \to 0^{+} } (0)\\0$

4 0

2 years ago

Sweets cost 6p how much would 43 sweets cost?

SCORPION-xisa [38]

The answer is 258 pennies

7 0

3 years ago

2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar

tia_tia [17]

9514 1404 393

Answer:

a) E = 6500 -50d

b) 5000 kWh

c) the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

Given:

starting excess (E): 6500 kWh

usage: 50 kWh/day (d)

Find:

a) E(d)

b) E(30)

c) E(150)

Solution:

a) The exces is linearly decreasing with the number of days, so we have ...

E(d) = 6500 -50d

b) After 30 days, the excess remaining is ...

E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

c) After 150 days, the excess remaining would be ...

E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0

3 years ago