Answer:
5 should be subtracted from each term
Step-by-step explanation:
Cross multiply,
1 * (11 - x) = 2*(8-x)
11 -x = 2*8 - 2*x
11 - x = 16 - 2x
Subtract 11 from both sides,
-x = 16 - 2x - 11
-x = 5 - 2x
Add 2x to both sides
-x +2x = 5 - 2 + 2x
x = 5
The third choice is appropriate.
an = 5 - 3(n - 1); all integers n ≥ 1
_____
This equation follows the form for the general term of an arithmetic sequence.
an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.
X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
X= 20 y= 100
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The x variable, that is being multiplied.
