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cupoosta [38]
3 years ago
10

Use the least common denominator to write an equivalent fraction for each fractoin a .5/6 2/9 b. 1/12 3/8 c. 5/9 2/15

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0
D ksksnddiiwjejwkwakds
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mai has 36$ to spend on movie tickets each movie ticket cost 4.50$ how many ticket can she buy multiplication problem
-Dominant- [34]

Answer:

8

Step-by-step explanation:

Mai has $36 and each movie ticket is $4.50.

You wanna divide 36 by 4.50 to find out how much tickets she can purchase which is 8.

6 0
2 years ago
How do u solve this question in the picture
dedylja [7]
1/2 over -2/5 + (-1/4) 

10/20 over -8/20 + (-5/20) 

1 5/20 + (-5/20) 

1

The answer is 1
6 0
3 years ago
Please help I’ll give you brainiest :)
juin [17]

Answer:

i think its b

Step-by-step explanation:

4 0
3 years ago
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Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
(-4, 6) and (3.-7)<br> Find the distance between each pair of parts
Misha Larkins [42]

Answer:

√218

Step-by-step explanation:

Distance-√(x2-x1)+(y2-y1)

4 0
3 years ago
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