Answer:
1. Transversal y intersects lines m and n; <1 ~= <2 (Given)
2. <1 ~= <3 (Vertical Angles Theorem)
3. <2 ~= <3 (Transitive Property of Congruence)
4. m || n (Converse of Alternate Interior Angles Theorem)
Answer:
Step-by-step explanation:
<u>Seven less than the product of a number n and 1/6 is no more than 94, translating:</u>
<u>Solving for n:</u>
- n/6 ≤ 94 + 7
- n/6 ≤ 101
- n ≤ 101*6
- n ≤ 606
Answer:
I) If method I is used, population of generalization will include all those people who may have varying exercising habits or routines. They may or may not have a regular excersing habit. In his case sample is taken from a more diverse population
II) Population of generalization will include people who will have similar excersing routines and habits if method II is used since sample is choosen from a specific population
Step-by-step explanation:
past excercising habits may affect the change in intensity to a targeted excersise in different manner. So in method I a greater diversity is included and result of excersing with or without a trainer will account for greater number of variables than method II.
Answer:
it is so unclear to say . If any more information is given, then only it can be answered. I don't think 196 is so special to be classified.
Answer:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
Sample of 421 new car buyers, 75 preferred foreign cars. So 
85% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
