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MissTica
3 years ago
9

What single transformation maps ABC onto A'B'C'?

Mathematics
2 answers:
TEA [102]3 years ago
7 0


Plz mark me as brainliest !

Is the second one :
Rotation 90 degrees counterclockwise about the Origen
Nutka1998 [239]3 years ago
4 0
A 90 Degree counter clockwise rotation 
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The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for
Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

<em>So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;</em>

        P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

where, s^{2} = sample variance = 1.88

           \sigma^{2} = population variance

            n = sample of windshields = 83

So, 95% confidence interval for population variance, \sigma^{2} is;

P(58.85 < \chi^{2} __8_2 < 108.9) = 0.95 {As the table of \chi^{2} at 82 degree of freedom

                                              gives critical values of 58.85 & 108.9}

P(58.85 < \frac{(n-1)s^{2} }{\sigma^{2} } < 108.9) = 0.95

P( \frac{ 58.85}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{108.9}{(n-1)s^{2} } ) = 0.95

P( \frac{ (n-1)s^{2}}{108.9 } < \sigma^{2} < \frac{ (n-1)s^{2}}{58.85 } ) = 0.95

<em><u>95% confidence interval for</u></em> \sigma^{2} = ( \frac{ (n-1)s^{2}}{108.9 } , \frac{ (n-1)s^{2}}{58.85 } )

                                                  = ( \frac{ (83-1)\times 1.88}{108.9 } , \frac{ (83-1)\times 1.88}{58.85 } )

                                                  = (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

8 0
3 years ago
Tomas is planning out a rail trail using a map with a marked grid. The head of the trail, which has an information kiosk, is loc
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Since the head of the trail is located at (3, 0), the trail moves 3 units north with each move and the map extends to 40 units to the north, then the number of 3 units in 40 units is 13. 

Thus, he can move only thirteen 3 units to the north and hence, thirteen 1 unit to the east.

Thus, the x-coordinate of the foot of the trail is 3 + 13 = 16 and the y-coordinate of the foot of the trail is 0 + 3(13) = 39.

Therefore, the location of the foot of the trail is at (16, 39).
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The Answer is 2.

Step-by-step explanation:

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