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Ipatiy [6.2K]
3 years ago
9

Given that 3y = x + 6 and y = kx + 12 are perpendicular, find the value of k

Mathematics
1 answer:
fenix001 [56]3 years ago
6 0

k = -3

Step-by-step explanation:

Let's rewrite the equations in their slope-intercept forms:

y = \frac{1}{3}x + 2\:\:\:\:\:\:\:(1)

y = kx + 12\:\:\:\:\:(2)

In order for Eqn(2) to be perpendicular to Eqn(1), the slope of Eqn(2) must be the negative reciprocal of that of Eqn(1). Therefore, k = -3.

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