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3 years ago

Pressure Question! Please helpp, it's attached below xx

Mathematics

1 answer:

Natali5045456 [20]3 years ago

5 0

Answer:

ttd2

Step-by-step explanation:

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Help me please. I don’t understand this math. My math teacher is mean. :(((((

Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is $5cm^3$

And length is $\frac{3}{4}$ and width is $1\frac{1}{3}$

That is V=5cm^3[/tex] , $l=\frac{3}{4}cm$ and $w=1\frac{1}{3}cm$

We have the volume of the rectangular prism V=lwh cubic centimeter

$V=lwhcm^3$

Substituting the values in above formula

$5=\frac{3}{4}\times 1\frac{1}{3}\times h$

$5=\frac{3}{4}\times \frac{4}{3}\times h$

$5=1\times h$

$5=h$

Rewritting as below

$h=5cm$

Therefore the height is 5cm

5 0

4 years ago

Read 2 more answers

How many solutions does the following equation have? ln(x2 + 4x − 5) = 0

lisov135 [29]

Alrighty
remember
$log_a(b)=c$ means $a^c=b$
and
$ln(x)=log_e(x)$
and
$x^0=1$ for all real values of x
so

$ln(x^2+4x-5)=0$ means
$log_e(x^2+4x-5)=0$ means
$e^0=x^2+4x-5$ which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square
$x=-2+\sqrt{10}$ and $x=-2-\sqrt{10}$
2 solutions

7 0

3 years ago

Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred

Ksivusya [100]

1. $m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}$ , then $m\angle ABC=m\angle ACD$ and triangles ADC and ACB are similar by AAA theorem.

2. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{AC}{AB}= \dfrac{AD}{AC}$ .

3. Knowing lengths you could state that $\dfrac{b}{c}= \dfrac{e}{b}$ .

4. This ratio is equivalent to $b^2=ce$ .

5. $m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}$ , then $m\angle BAC=m\angle BCD$ and triangles BDC and BCA are similar by AAA theorem.