Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
This question is unsolvable this might be a trick question but it is not solvable. Hope this helps! ;D
The sampling distribution is illustrated below.
<h3>How to illustrate the sampling?</h3>
Based on the information given, the population is illustrated as 1, 4, 7. The sample without replacement will be:
<u>Sample Mean</u>
1 and 4. 2.5
1 and 7. 4
4 and 7. 5.5
The population mean will be:
= (1 + 4 + 7)/3
= 4
The sample mean is an unbiased estimator of the population mean.
The sampling with replacement illustrates that the mean will be:
= 36/9 = 4
Also, when n = 3, the number of samples will be:
= 3³ = 27
Learn more about sampling on:
brainly.com/question/17831271
#SPJ1
Answer:
f(4) = 85 1/3 or 85.333...
Step-by-step explanation:
To find f(4), you must substitute 4 in place of x whenever x appears:
f(x) =
*
f(4) =
* 
Next, simplify the exponent:
f(4) =
* 256
Finally, multiply:
f(4) = 85 1/3 or 85.333...