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Elanso [62]
3 years ago
7

What is the area of the shaded region between the two z-scores indicated in the standard normal curve shown below. z=-1.23 z=0.8

3

Mathematics
1 answer:
Reika [66]3 years ago
6 0

Answer:

Correct option A: 0.6874

Step-by-step explanation:

Hello!

To calculate the area within the interval [-1.23; 0.83], you have to subtract to the probability accumulated till the lower value to the probability accumulated to the higher value, symbolically:

P(Z≤0.83)-P(Z≤-1.23)

You have to use the Z table to look for the corresponding values of probability. The negative value is in the left entry and the positive value is in the right entry. The first column shows the integer and first decimal value, the second decimal value is in the first row, you cross both values and find the value of probability.

P(Z≤0.83)-P(Z≤-1.23)= 0.7967 - 0.1093= 0.6874

I hope it helps!

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Marie has a part time job. She earns $7 an hour. She makes at most $143.50 per week. What is the greatest number of hours that s
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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
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\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

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Kindly consider the equilateral \triangle ABC as attached in the answer area.

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Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

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Suppose GRE Quantitative scores are normally distributed with a mean of 587587 and a standard deviation of 152152. A university
Solnce55 [7]

Answer:

The minimum score required for the job offer is 751.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 587, \sigma = 152

What is the minimum score required for the job offer?

Top 14%, so the minimum score is the 100-14 = 86th percentile, which is X when Z has a pvalue of 0.86. So X when Z = 1.08.

Then

Z = \frac{X - \mu}{\sigma}

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X - 587 = 1.08*152

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Rounding to the nearest whole number:

The minimum score required for the job offer is 751.

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