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Elanso [62]
3 years ago
7

What is the area of the shaded region between the two z-scores indicated in the standard normal curve shown below. z=-1.23 z=0.8

3

Mathematics
1 answer:
Reika [66]3 years ago
6 0

Answer:

Correct option A: 0.6874

Step-by-step explanation:

Hello!

To calculate the area within the interval [-1.23; 0.83], you have to subtract to the probability accumulated till the lower value to the probability accumulated to the higher value, symbolically:

P(Z≤0.83)-P(Z≤-1.23)

You have to use the Z table to look for the corresponding values of probability. The negative value is in the left entry and the positive value is in the right entry. The first column shows the integer and first decimal value, the second decimal value is in the first row, you cross both values and find the value of probability.

P(Z≤0.83)-P(Z≤-1.23)= 0.7967 - 0.1093= 0.6874

I hope it helps!

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Answer:

D & B

Step-by-step explanation:

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3 years ago
9x-7=-7 please help me please
Sholpan [36]

Answer:

Step-by-step explanation:

9x-7=-7

9x - 7 + 7 = -7 + 7

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I hope this will help you

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An automobile manufacturer can produce up to 300 cars per day. The profit made from the sale of these vehicles can be modeled by
drek231 [11]

Answer:  175

<u>Step-by-step explanation:</u>

To find maximum, we need to find the vertex.  

The x-value of the vertex is the number of automobiles that should be made and sold.  <em>The y-value is the maximum profit.</em>

P(x) = -10x² + 3500x - 66,000

         a=-10, b = 3500, c=-66,000

x=\dfrac{-b}{2a}

x=\dfrac{-(3500)}{2(-10)}

x = \dfrac{-3500}{-20}

x = 175


<u>BONUS:</u>

The maximum profit is: P(x) = -10(175)² + 3500(175) - 66,000

                                              = -300,625 + 612,500 - 66,000

                                              = 245,875


8 0
3 years ago
Percent Means Tenth?
WITCHER [35]

Answer:

ten percent - a tenth part; one part in ten equal parts. one-tenth, tenth, tenth part. common fraction, simple fraction - the quotient of two integers. Based on WordNet 3.0, Farlex clipart collection.

8 0
3 years ago
N is a positive integer
Murrr4er [49]

Part (1)

n is some positive integer. Let's say for now that n is even. So n = 2k, for some integer k

This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

where m = k(2k-1) is an integer

The result 2m is even showing that n(n-1) is even

------------

Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

Now multiply n and n-1

n(n-1) = (2k+1)(2k) = 2k(2k+1) = 2m

where m = k(2k+1) is an integer

We've shown that n(n-1) is even here as well.

------------

So overall, n(n-1) is even regardless if n is even or if n is odd.

Either n or n-1 will be even. If you multiply an even number with any number, the result will be even.

=======================================================

Part (2)

n is some positive integer

2n is always even since 2 is a factor of 2n

2n+1 is always odd because we're adding 1 to an even number. The sequence of integers goes even,odd,even,odd, etc and it does this forever.

-----------

Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

The 0.5 at the end is not an integer, so there's no way that (2n+1)/2 is an integer; therefore 2n+1 is odd.

6 0
3 years ago
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