If the area of a square is 50 m2, then the length of each side will be $\sqrt{50}$ m, to get the diagonal length, after dividing the square by joining the points of the diagonal with a line, it forms two right angles with length $\sqrt{50}$ m each.

the diagonal length represent the hypotenuse side of each of the right angle, knowing the pythagoras theorem:

$(hyp)^{2} = (opp)^{2} + (Adj)^{2}$ , so we have:

$(diagonal)^{2} = 50 + 50$

$(diagonal)^{2} = 100$

diagonal = 10 m

6 0

3 years ago

(45pts) An elevator holds at most 1,400 pounds. A team of movers and their cart have a combined weight of 1,200 pounds. If each

emmainna [20.7K]

Let $x$ be the number of boxes the team brings with them. Their weight combined with the boxes can't exceed the capacity of 1400. Assuming the elevator runs fine at that exact weight, you want to find the number of boxes, each of which contributes 40 pounds. This is given by the equation

$1400=1200+40x$

Solving for $x$ , you have

$1400=1200-40x$
$200=40x$
$x=5$

So the team can bring *at most* 5 boxes at a time.

4 0

3 years ago