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madam [21]
3 years ago
7

What is the approximate length of minor arc XZ? Round to the nearest tenth of a meter

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Answer:

?

Step-by-step explanation:

We can't see minor arc xz, you need a picture

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One number is nine more than the other. Their sum is 33. Find the numbers. (Enter your answers as a comma-separated list.)
Bas_tet [7]

Answer:

The numbers are 12, 21.

Step-by-step explanation:

x+(x+9)=33

x+x+9=33

2x+9=33

2x=33-9

2x=24

x=24/2

x=12

--------

x+9=12+9=21

Please mark me as Brainliest if you're satisfied with the answer.

5 0
2 years ago
Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak
crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28

We can now calculate the probabilities:

P(0.47

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2

We can now calculate the probabilities:

P(0.47

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

8 0
2 years ago
Please help, show work!!! :))
otez555 [7]
25.59- 9.99= 15.60
15.60/ 0.05 = 312
312 minutes this month
4 0
2 years ago
mark pays a $2 enterance fee and $0.75 every time he plays his favorite video game. If he has $17 , how many video games can he
Murrr4er [49]

Answer:

6 video games

Step-by-step explanation:

divide 17 by 2.75

5 0
3 years ago
The figure shows two parallel lines KL and NO cut by the transversals KO and LN.
Sever21 [200]

Answer:

(A)  

Step-by-step explanation:

From the given figure, we have to prove whether the two given triangles are congruent or similar.

Thus, From the figure, ∠3=∠4 (Vertically opposite angles)

Since, KL and NO are parallel lines and KO and LN are transversals, then

measure angle 1= measure angle 5 that is ∠1=∠5(Alternate angles).

Thus, by AA similarity rule, ΔKLM is similar to ΔONM.

Thus, Option A that is Triangle KLM is similar to triangle ONM because measure of angle 3 equals measure of angle 4 and measure of angle 1 equals measure of angle 5 is correct.

8 0
2 years ago
Read 2 more answers
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