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RideAnS [48]
3 years ago
6

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 12 - x2? (4 points)

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer: 16 square units

Step-by-step explanation:

let the vertex in quadrant I be (x,y)  

then the vertex in quadratnt II is (-x,y)  

base of the rectangle = 2x  

height of the rectangle = y  

Area = xy  

= x(12 - x²)  

= -x³ + 12x  

d(area)/dx = 3x² - 12 = 0 for a maximum of area  

3x² = 12  

x² = 4  

x = ±2  

y = 12-4 = 8

So, the largest area = 2 x 8 = 16 square units

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Step-by-step explanation:

1) The absolute value of -8 is added to the absolute value of 5. 8+5=13

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3) Take what's given and create an equation to solve. 4x + 15 +39 =110. 4x = 110 - (15+39).

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