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ivanzaharov [21]
2 years ago
10

If the perimeter of a rectangle is 800 and the length is 30 more than the width how much is the width?

Mathematics
1 answer:
Alex777 [14]2 years ago
8 0
The width is 180 units, considering my work.

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18/s=3 what’s the value of s
Lilit [14]

Answer:

s=6

Step-by-step explanation:

18/s = 3

Multiply each side by s

18/s *s = 3*s

18 =3s

Divide each side by 3

18/3 =3s/3

6 =s

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3 years ago
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A bale of hay was 100 cm long by 40 cm wide by 20 cm tall. What is the volume of the bale of hay?
Ksenya-84 [330]

Answer:

80000 cm cubed

Step-by-step explanation:

L*W*H

100*20*20

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2 years ago
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Please help me I’m stuck!!!
Klio2033 [76]

Answer:

The point (0, 6.7) is the point where the ball was launched.

Step-by-step explanation:

The ball was launched from a point 6.7 feet from ground level.

In this scenario (ball tossed toward the goal), the constant  c  at the end of the function formula gives you the initial position (height).

5 0
2 years ago
PLEASE HELP!
Leona [35]

Answer:

The initial temperature of the object was 37.6

Step-by-step explanation:

we have

f(t)=Ce^{(-kt)} +20

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

Find the value of the constant C

we have the ordered pair (4,35)

substitute in the equation and solve for C

35=Ce^{(-0.0399*4)} +20\\Ce^{(-0.0399*4)}=15\\C=15/e^{(-0.0399*4)}\\C=17.6

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

so

For t=0

f(0)=(17.6)e^{(-k*0)} +20\\f(0)=17.6 +20\\f(0)=37.6

therefore

The initial temperature of the object was 37.6 (I not include units)

7 0
3 years ago
Please help! Its for my big test tomorrow!
Travka [436]

Answer:

# The solution x = -5

# The solution is x = 1

# The solution is x = 6.4

# The solution is x = 4

# The solution is 1.7427

# The solution is 0.190757

Step-by-step explanation:

* Lets revise some rules of the exponents and the logarithmic equation

# Exponent rules:

1- b^m  ×  b^n  =  b^(m + n) ⇒ in multiplication if they have same base

  we add  the power

2- b^m  ÷  b^n =  b^(m – n) ⇒  in division if they have same base we

   subtract  the power

3- (b^m)^n = b^(mn) ⇒ if we have power over power we multiply

   them

4- a^m × b^m = (ab)^m ⇒ if we multiply different bases with same  

   power then we multiply them ad put over the answer the power

5- b^(-m) = 1/(b^m)  (for all nonzero real numbers b) ⇒ If we have

   negative power we reciprocal the base to get positive power

6- If  a^m  =  a^n  ,  then  m  =  n ⇒ equal bases get equal powers

7- If  a^m  =  b^m  ,  then  a  =  b    or    m  =  0

# Logarithmic rules:

1- log_{a}b=n-----a^{n}=b

2- loga_{1}=0---log_{a}a=1---ln(e)=1

3- log_{a}q+log_{a}p=log_{a}qp

4- log_{a}q-log_{a}p=log_{a}\frac{q}{p}

5- log_{a}q^{n}=nlog_{a}q

* Now lets solve the problems

# 3^{x+1}=9^{x+3}

- Change the base 9 to 3²

∴ 9^{x+3}=3^{2(x+3)}=3^{2x+6}

∴ 3^{x+1}=3^{2x+6}

- Same bases have equal powers

∴ x + 1 = 2x + 6 ⇒ subtract x and 6 from both sides

∴ 1 - 6 = 2x - x

∴ -5 = x

* The solution x = -5

# ㏒(9x - 2) = ㏒(4x + 3)

- If ㏒(a) = ㏒(b), then a = b

∴ 9x - 2 = 4x + 3 ⇒ subtract 4x from both sides and add 2 to both sides

∴ 5x = 5 ⇒ divide both sides by 5

∴ x = 1

* The solution is x = 1

# log_{6}(5x+4)=2

- Use the 1st rule in the logarithmic equation

∴ 6² = 5x + 4

∴ 36 = 5x + 4 ⇒ subtract 4 from both sides

∴ 32 = 5x ⇒ divide both sides by 5

∴ 6.4 = x

* The solution is x = 6.4

# log_{2}x+log_{2}(x-3)=2

- Use the rule 3 in the logarithmic equation

∴ log_{2}x(x-3)=2

- Use the 1st rule in the logarithmic equation

∴ 2² = x(x - 3) ⇒ simplify

∴ 4 = x² - 3x ⇒ subtract 4 from both sides

∴ x² - 3x - 4 = 0 ⇒ factorize it into two brackets

∴ (x - 4)(x + 1) = 0 ⇒ equate each bract by 0

∴ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

OR

∵ x + 1 = 0 ⇒ subtract 1 from both sides

∴ x = -1

- We will reject this answer because when we substitute the value

 of x in the given equation we will find log_{2}(-1) and this

 value is undefined, there is no logarithm for negative number

* The solution is x = 4

# log_{4}11.2=x

- You can use the calculator directly to find x

∴ x = 1.7427

* The solution is 1.7427

# 2e^{8x}=9.2 ⇒ divide the both sides by 2

∴ e^{8x}=4.6

- Insert ln for both sides

∴ lne^{8x}=ln(4.6)

- Use the rule ln(e^{n})=nln(e) ⇒ ln(e) = 1

∴ 8x = ln(4.6) ⇒ divide both sides by 8

∴ x = ln(4.6)/8 = 0.190757

* The solution is 0.190757

7 0
3 years ago
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