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Arisa [49]
3 years ago
10

Can someone help me with this it is system of equations and you have to find the cost of each one

Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

1 cupcake = $3.75

1 ice-cream = $4.50

1 doughnut = $1.50

Step-by-step explanation:

2 ice-cream + 1 cup cake = $12.75 ------------ [ 1 ]

1 ice-cream + 2 doughnuts = $7.50 ------------ [ 2 ]

1 cup cake + 1 doughnut + 1 ice-cream = $9.75 ------------ [ 3 ]

From [ 1 ] :

2 ice-cream + 1 cup cake = $12.75

1 cupcake = $12.75 - 2 ice-cream

Substitute [ 1 ] into [ 3 ]:

1 cup cake + 1 doughnut + 1 ice-cream = $9.75

$12.75 - 2 ice-cream + 1 doughnut + 1 ice-cream = $9.75

1 doughnut - 1 ice-cream = -$3  ------------ [ 4 ]

[ 2 ] + [ 4 ] :

3 doughnuts = $4.75

1 doughnut = $1.50

Substitute (1 doughnut = $1.50) into [ 2] :

1 ice-cream + 2 doughnuts = $7.50

1 ice-cream + 2 x $1.50 = $7.50

1 ice-cream + $3 = $7.50

1 ice-cream = $4.50

Substitute (1 ice-cream = $4.50) into [ 1 ]:

2 ice-cream + 1 cup cake = $12.75

2 x $4.50 + 1 cup cake = $12.75

1 cupcake = $12.75 - $9

1 cupcake = $3.75

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Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

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So we have:

\sin^2(x) + (1/4)^2 = 1sin

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Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

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Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

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sin(x) < 0

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\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

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sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

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\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

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∗

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This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

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