Problem One
Find AM
AM = 71.5 - 22 = 49.5
Step Two
State the Givens.
AM = 49.5
MN = 71.5
MB = x
MP = 97.5
Step Three
Set up the Proportion
AM : NM :: x : PM
49.5 : 71.5 :: x : 97.5
Substitute and solve
49.5 / 71.5 = x / 97.5 Cross Multiply
49.5 * 97.5 = 71.5 * x Combine the numbers on the left.
4860.375 = 71.5 * x Divide by 71.5
4860.375 / 71.5 = x
x = 67.98
Problem Two
Remark
This is just a straight application of the Pythagorean Theorem
a^2 + b^2 = c^2
a = 10
b = 24
c = ??
10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
sqrt(c^2) = sqrt(676)
c = 26 <<<< answer
<span>1. For the data in the table, does y vary directly with X? If it does write an equation for the direct variation.(X,y) (8,11) (16,22) (24,33)
</span><span>
Yes y=1.375x
</span><span>2.for the data in the table, does y vary directly with X? If it does write an equation for the direct variation. (X,y) (16,4) (32,16) (48,36)
</span>No y does not very directly with x*** <span>
</span><span>3. (Time/hour,distance/miles)(4,233) (6,348) (8,464) (10, 580)
Express the relationship between distance and time in a simplified form as a unit rate. Determine which statement correctly interprets this relationship.
</span><span>58/1 your car travels 58 miles in 1 hour
</span><span>4.what is the slope of the line that passes through the pair of points (2,5) and (8,3)
</span>-1/3
<span>4.what is the slope of the line that passes through the pair of points (-5.2,8.7) and (-3.2,2.7)
</span>
-3
<span>5. What is the slope of the line that passes through the pair of points (3/2,-2) and (-3,7/3)
-26/27
</span><span>6.write an equation in point slope from for the line through the given point with the given slope (5,2) m=3
Y-2=3(X-5)
7. Write an equation in point slope form for the line through the given point with the given slope (-3,-5) m=-2/5
Y+5=-2/5(X+3)
</span><span>8. Write an equation in point slope from for the line through the given point with the given slope. (4,-7) m=-0.54
Y+7=-0.54(x-4)
9. The table shows the height of a plant as it grows. Which equation in point slope from gives the plants height (time,plant height) (2,16)(4,32)(6,48)(8,64)
Y-16=8(X-2)***
</span>
<span>10. Write y=-2/3x+7 in standard form
2x+3y=21
11. Write y=-1/2x+1 in standard form using integers
X+2y=2
</span>
A(10) =126,000 (1.02)^10 = $153,593.30
Answer:
a) = 4.5
b) = 3.3
Step-by-step explanation:
Before solving our problems given to us let us under stand the rule of cube roots
It says ![\sqrt[3]{x \times x \times x} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%7D%20%3D%20x)
-----(A)
Also
![\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%20%5Ctimes%20y%20%5Ctimes%20y%20%5Ctimes%20y%7D%20%3D%20x%20%5Ctimes%20y)
---(B)
Now let us see each part one by one
a) we have
![\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%2B%20%5Csqrt%5B3%5D%7B0.027%7D%20%2B%20%5Csqrt%5B3%5D%7B0.008%7D)
Now 64 = 4 x 4 x 4
0.027 = 0.3 x 0.3 x 0.3
0.008 = 0.2 x 0.2 x 0.2
substituting these values
![\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20%2B%20%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%7D%20%2B%20%5Csqrt%5B3%5D%7B0.2%20%5Ctimes%200.2%20%5Ctimes%200.2%7D)
Applying Rule A in above
4.5
b) we have ![\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%20%5Ctimes%2011%20%5Ctimes%2011%20%5Ctimes%2011%7D)
Applying the B rule in this
3.3
