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SOVA2 [1]
3 years ago
11

Rectangle VWXY is dilated by a scale factor of 2 to form rectangle V'W'X'Y'. Side X'Y'

Mathematics
1 answer:
posledela3 years ago
8 0

9514 1404 393

Answer:

  11

Step-by-step explanation:

X'Y' = 2XY . . . . lengths are related by the dilation factor

22 = 2XY . . . substitute the given value

11 = XY . . . . . divide by 2

The measure of side XY is 11.

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If g=4 and h = -3 Evaluate:5g-7h
Sunny_sXe [5.5K]

Answer:

41

Step-by-step explanation:

5(4) - 7(-3)

20 + 21 (because it's a negative times a negative and that equals a positive)

41

3 0
3 years ago
Read 2 more answers
In a class of 30 students, 19 are studying French (F), 12 are studying Spanish (S) and 7 are studying both French and Spanish. H
Fiesta28 [93]

Answer: There are 14 students not taking any foreign languages.

Step-by-step explanation: Take the total number of  students and subtract it by the number of students who are taking each class. So you would get 19 for French, 12 for Spanish, and 7 for both. Then you would add those numbers up and get a total of 38. You would then do the same except subtract each total of students by 30 to find how many of the 30 are not taking each class or both. You would then get 11 for French, 18 for Spanish, and 23 for both. Add those numbers up and get 52. Then you would subtract 38 from 52 thus giving the final answer 14.

5 0
4 years ago
Which of the following is not a function?
QveST [7]

Answer:

It is the chart on the left beacuse it reapetsX 2

6 0
3 years ago
Absulute maximum definition
bonufazy [111]

Answer:

diffusion

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6 0
3 years ago
Given the following cards, what is the probability of drawing a blue card, not replacing it, and then drawing another blue card?
ValentinkaMS [17]
There are 5 cards total, "sample space of 5", there are 3 blue cards, "favorable outcomes of 3".

the chances of getting the first blue will be 3/5.

once the first blue is pulled out, and not put back, the sample spaced changed to 4, and since there are only 2 blue cards, the favorable outcomes changed to only 2.

the chances of getting the 2nd blue card is 2/4 or 1/2.

P( second blue | first blue) = P(first blue) * P(second blue)

\bf \stackrel{first~blue}{\cfrac{3}{5}}\stackrel{AND}{\cdot} \stackrel{second~blue}{\cfrac{2}{4}}\implies \cfrac{3}{10}
7 0
3 years ago
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