Answer:
2
Step-by-step explanation:
You would replace the x with -2x so you would end up with -2×-2 and that is 4 then minus 2 is 2.
Answer:
5 units
Step-by-step explanation:
3x + 4y = 8
4y = -3x+8
y = -3/4+2
The shortest distance between a point and a line is the perpendicular line.
Slope of the perpendicular line: 4/3 and point (-3,-2)
b = -2-(4/3)(-3) = 2
Equation of the perpendicular line: y=4/3x+2
y is equal y
4/3x+2= -3/4x+2
4/3x +3/4x = 2-2
x = 0
Plug x=0 into one of the equations to find y
y = 4/3(0) + 2
y = 2
(0,2) and (-3,-2)
Distance = sqrt [(-3-0)^2 + (-2-2)^2]
Sqrt (-3)^2+ (-4)^2
Sqrt 25 = 5
This question is incomplete, the complete question is;
X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)
Answer:
P( W> 10) is 0.1587
Step-by-step explanation:
Given that;
X ⇒ N( 13.9, 5.2 )
Y ⇒ N( 6.9, 3.8 )
W = X - Y
Therefore
E(W) = E(X) - E(Y)
= 13.9 - 6.9 = 7
Var(W) = Var(X) + Var(Y) -2COV(X.Y)
[ COV(X,Y) = 0 because they are independent]
Var(W) = 5.2 + 3.8 + 0
= 9
Therefore
W ⇒ N( 7, 9 )
so
P( W > 10 )
= 1 - P( W ≤ 10 )
= 1 - P( W-7 /3 ≤ 10-7 /3 )
= 1 - P( Z ≤ 1 ) [ Z = W-7 / 3 ⇒ N(0, 1) ]
from Standard normal distribution table, P( Z ≤ 1 ) = 0.8413
so
1 - P( Z ≤ 1 ) = 1 - 0.8413 = 0.1587
Therefore P( W> 10) is 0.1587
