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3 years ago

5

Fourth geometry question

2 answers:

CaHeK987 [17]3 years ago

7 0

Δ DEC is a reflection of ΔABC across line k.

vesna_86 [32]3 years ago

7 0

Lines DEC are a Reflection of lines ABC and the way you van tell is you visualize in your mind flipping the image to the right or to the left it doesn't matter but if they line up then that is how you know it is a reflection.
I hope this helps a lot and have a good day.

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dangina [55]

Answer:

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Step-by-step explanation:

Given:

$tan\theta =\frac{3}{4}$

$cot\theta =\frac{4}{3}$ [∵ $cot\theta =\frac{1}{tan\theta}$ ]

Squaring both sides.

$cot^2\theta =\frac{4^2}{3^2}=\frac{16}{9}$

$csc^2\theta -1=\frac{16}{9}$ [∵ $cot^2\theta =csc^2\theta-1]$ ]

Adding 1 to both sides.

$csc^2\theta -1+1=\frac{16}{9}+1$

$csc^2\theta =\frac{16}{9}+1$

$csc^2\theta=\frac{16}{9} +\frac{9}{9}$ [Taking LCD=9 and adding fractions ]

$csc^2\theta=\frac{16+9}{9}$

$csc^2\theta=\frac{25}{9}$

Taking square root both sides.

$\sqrt{csc^2\theta}=\sqrt{\frac{25}{9}}$

∴ $csc\theta=\frac{5}{3}$

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3 years ago

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trapecia [35]

Answer:

130

Step-by-step explanation:

<u>Probability of green:</u>

P= 39/300

<u>Number of attempts: </u>

1000

<u>Expected number of landing on green: </u>

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