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emmainna [20.7K]
3 years ago
15

How are the reproductive cycles of a fungus and a pteridophyte similar? A. Both organisms form fruiting bodies that produce dipl

oid seeds. B. Both organisms reproduce sexually when two haploid hyphae fuse. C. Both organisms produce haploid spores and exhibit diploid and haploid stages. D. Both organisms exhibit a diploid stage and are only able to reproduce asexually. Reset Next Plants and Fungi: Mastery Test
Biology
2 answers:
snow_lady [41]3 years ago
7 0

Both organisms exhibit a diploid stage and are only able to reproduce asexually.

schepotkina [342]3 years ago
3 0

The correct answer is option C, that is, both the organisms generate haploid spores and exhibit diploid and haploid stages.  

The sporophyte (of the haploid stage) in pteridophytes produce spores. The diploid stage in pteridophytes may take place when two of the spores combines and give rise to a prothallus, that is, the diploid stage of the pteridophytes.  

In fungi, the production of spores takes place by sporangiophores (haploid stage). At a certain stage, two horizontal hyphae among the two species of fungi, may amalgamate at the tips and produce a zygote (diploid) via plasmogamy and karyogamy.  


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What is not a dissolved gas present in the ocean
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The correct answer is option B, hydrogen.

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5 0
3 years ago
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viva [34]

Answer:

Explanation:

The Genotype of the  woman is XCbXN

The man XNY

Since the allele for the color blindness is carried on one of the X -chromosomes of the  carrier mother, then  the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal  allele from the  mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal  X allele from the father.

Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes

1. XNY vs XCbXN.Then the one of the  boys will be colorblind  and the one of  girls will be carriers. XNXCb, XNXN, XCbY,XNY  50 %

2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle

Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).

The proportions that will be  the females  since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls  take the defective allele from the mothers and take normal from the father,they will all  be carriers,since the X of the father is normal.

They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.

5 0
3 years ago
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An enzyme that can bind to and break apart molecules of lactose should also be able to bind: a. fatty acids. b. amino acids. c.
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