First= -2x+2y+3z=0
= -2x+2y+3z +-2y=0+(-2y)
-2x+3z=-2y
-2x+3z=-2y+-3z
-2x=-2y-3z
Divide both by negative two
-2x/-2=-2y-3z/-2
x=y+3/2z that’s the answer.
Use this to help you with other equations
Answer:
0 maybe?
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
16+3:19
11+8:19
19=19
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
C.
Step-by-step explanation:
