Answer: -3x²-9x+84
Step-by-step explanation:
Let the zeros be r1 and R2
The equation of a parabola going through those two zeros is
y=a(x−r1)(x−r2)
Slope intercept looks like this:
y = ax + c
So:
-5y = 9x + 35
We need to isolate y, so divide both sides by -5:
y = -
x - 7
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
I am sorry but there is no attachment. Please attach the file.
It is m4 in my opinion i’m not sure tho