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marusya05 [52]
4 years ago
14

Show that the system has no solution. x + 2y = -4 y = -1/2x - 4

Mathematics
1 answer:
erica [24]4 years ago
7 0

Step-by-step explanation:

TO show that this system has no solution, use the y value in the second equation and put it in for y in the first. Then solve.

x + 2y = -4

x + 2(-1/2x - 4) = -4

x  - x - 8 = -4

-8 = -4

Because this is an incorrect statement, we can tell there is no solution.

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PLZZ HELP ME!!!!!! PLZ, I will mark brainliest!!!
Ivahew [28]

Answer:

19 691 miles

Step-by-step explanation:

Last year, it drove 100%, which is 196,910. This year, it drove 90% lesser, so it actually only drove: 100% - 90% = 10%.

10% as a fraction is \frac{10}{100}.

Distance travelled this year = \frac{10}{100} × 196 910

                                              = 19 691 miles

3 0
3 years ago
Please it’s urgent ........
grigory [225]

Answer:

77 degrees

Step-by-step explanation:

The angles of a triangle must add up to 180 degrees

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180-103=77

8 0
3 years ago
Read 2 more answers
sally is 1 year older than3 times the age of joe. chris is 5 years younger than 6 times the age of joe. if sally and chris are t
Lina20 [59]
6x - 5 = 3x + 1
-3x -3x
————————
3x - 5 = 1
+ 5 + 5
————————
3x = 6
—— —
3 3

x = 2
Joe is 2 years old.

~~~~~~~~~~~~~~~~
Check

6(2) - 5 = 3(2) + 1
12 - 5 = 6 + 1
✔️
7 = 7
5 0
4 years ago
What is the value of x squared + 2 x y / 2 * W + 3 * z for w=2, x=5, y=8 and z=3​
insens350 [35]

Answer: 114

Step-by-step explanation:

Plug in the numbers. 5*5+2*5*8/2*2+3*3=25+80+9=114

4 0
3 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
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