(5*7) - (5*4) = 35 - 20 = 15
you "distribute" the 5 but multiplying it to both numbers in the parentheses, and doing the subtraction.
Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Mark me as brainliest! :)
1/6 * 3/2 = 1/4
What is the question that you are asking? Do you need to write an equation?
