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Greeley [361]
4 years ago
14

If 4a + 6 = 12 - 2a what is 6a​

Mathematics
2 answers:
Sergio [31]4 years ago
5 0
ANSWER:-
a = 3




EXPLANATION:-
4a + 6 = 12 - 2a
4a - 2a = 12 - 6
2a = 6
a = 6/2
a = 3


HOPE IT HELPS!!!!!!!!!!
MARK ME THE BRAINLIEST!!!!!!!!
Gre4nikov [31]4 years ago
3 0

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

<em>Hey</em><em>!</em><em>!</em>

<em>Sol</em><em>ution</em>

<em> </em><em>4</em><em>a</em><em>+</em><em>6</em><em>=</em><em>1</em><em>2</em><em>-</em><em>2</em><em>a</em>

<em>or</em><em>,</em><em>4</em><em>a</em><em>+</em><em>2</em><em>a</em><em>=</em><em>1</em><em>2</em><em>-</em><em>6</em>

<em>or</em><em>,</em><em>6</em><em>a</em><em>=</em><em>6</em>

<em>or</em><em>,</em><em>a</em><em>=</em><em>6</em><em>/</em><em>6</em>

<em>a</em><em>=</em><em>1</em>

<em>The</em><em> </em><em>value</em><em> </em><em>of </em><em>a</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

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Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
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Option C:

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Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

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