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3 years ago

14

What is 8-p/2 is less than or equal to 4?

1 answer:

Vanyuwa [196]3 years ago

5 0

Less than (yes) p > -4

equal to (yes) p = -4

less than or equal to (yes) p (less than or equal to) -4)

I feel like I may have misinterpreted the question..

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A coral reef grew 3000 millimeters taller. How much did it grow in meters?

ANTONII [103]

3 meters equals 3000 mm

3 0

3 years ago

Saben como hacer una tabla de valores a partir de esto?: <img src="https://tex.z-dn.net/?f=f%28x%2C%20y%29%3D6x-11y" id="TexForm

solong [7]

Puedes explicar mas? Necesitamos a hacer una tabla o?

4 0

3 years ago

X^2+6x-19=0 pls helpppp

USPshnik [31]

Answer:

Step-by-step explanation:

Since this is not factorable, let's just complete the square:

$x^2+6x=19\\x^2+6x+9=28\\(x+3)^2=28\\x+3=\sqrt{28}\\x=2\sqrt{7}-3$

8 0

3 years ago

Lily's basketball team won 4/5 of their games. Lily scored points 2/3 of the games her team won. In waht fraction of her team's

igor_vitrenko [27]

$\huge\fcolorbox{blue}{aqua}{Answer:}$

════════════════════

Lily's basketball team won 4/5 of their games. Lily scored points 2/3 of the games her team won. In waht fraction of her team's winning games did Lily score points?

Answer: =D. $\frac{5}{6}$

Solution:

$\frac{ 2 }{ 3 } \div \frac{ 4 }{ 5 } =$

$\frac{2}{3}\times \left(\frac{5}{4}\right)$

$\frac{2\times 5}{3\times 4}$

$\frac{10}{12}$

= $\frac{5}{6}$

I reduced the fraction $\frac{10}{12}$ into the Lowest terms by doing extracting and cancelling out the $2$

= $\frac{5}{6}$

So the answer is letter D. $\frac{5}{6}$

════════════════════

Explanation:

#Carry on learning

4 0

3 years ago

Find the volume of the region between the cylinder z=3y^2 and the xy-plane that is bounded by the planes x=0,x=1 ,y=-1 and . z =

son4ous [18]

Answer:

The volume of the region V = 2

Step-by-step explanation:

Given that:

$z_1 = 3y^2$ ;

where initially;

$z_o = 0; \ x_o = 0; \ x_1 = 1; \ y_o= -1; \ y_1 = 1$

The volume of the region is given by a triple which is expressed as:

$V = \int_x \int_y \int_z \ dz \ dy \ dx$

$V = \int \limits ^{x_1 = 1}_{x_o=0} \int \limits ^{y_1 = 1}_{y_o=-1} \int \limits ^{z_1 = 3y^2}_{z_o=0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \int \limits ^{3y^2}_{0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [z \Bigg]^{3y^2}_{0} \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [3y^2 \Bigg] \ dy \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3y^3}{3} \Bigg]^1_{-1} \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3(1)^3}{3}- \dfrac{3(-1)^3}{3} \Bigg] \ dx$

$V = \int \limits ^{1}_{0} \Bigg [1-(-1)\Bigg] \ dx$

$V =2 \Bigg [x \Bigg] ^1_0$

V = 2

Thus, the volume of the region is 2

3 0

3 years ago