-30-6r=36
We move all terms to the left:
-30-6r-(36)=0
We add all the numbers together, and all the variables
-6r-66=0
We move all terms containing r to the left, all other terms to the right
-6r=66
r=66/-6
r=-11
Answer:
Actual height of church = 512 feet
Step-by-step explanation:
Given:
Scale model;
1 inch = 256 feet
Height of church (Scale model) = 2 inches
Find:
Actual height of church
Computation:
Actual height of church = Height of church (Scale model) x scale length
Actual height of church = 2 inches x 256 feet/inches
Actual height of church = 2 x 256 feet
Actual height of church = 512 feet
Well actually that is in the value place of the tenths not tens.
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR = 
= 17
Answer:
theres is not table shown
Step-by-step explanation:
