Step 1
Given;
Required; To find the difference in interest between the two periods.
Step 2
State the formula for simple interest
Step 3
Find the interest when the rate is 8%
Therefore the interest is given as;
Step 4
Find the interest in 1980 with a 20% rate
The interest is given as;
Step 5
Find the difference in interest between the two rates.
Hence, the difference in interest between the two rates = $11095.89
Answer:
3
Step-by-step explanation:
(x₁ , y₁) = (-1 , -2) & (x₂ , y₂) = (3 , 10)
![= \frac{10-[-2]}{3-[-1]}\\\\=\frac{10+2}{3+1}\\\\=\frac{12}{4}\\\\=4](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B10-%5B-2%5D%7D%7B3-%5B-1%5D%7D%5C%5C%5C%5C%3D%5Cfrac%7B10%2B2%7D%7B3%2B1%7D%5C%5C%5C%5C%3D%5Cfrac%7B12%7D%7B4%7D%5C%5C%5C%5C%3D4)
m = 4
y - y₁ = m (x - x₁)
y - [-2] = 4(x - [-1])
y + 2 = 4(x + 1)
y + 2 = 4x + 4
y = 4x + 4 - 2
y = 4x + 2
$1500 divided by 12 months = $125 per month. 0.75% x 120 (10 years x 12 months in each) = 90%. $125 x 120 = $15,000 + ($125 x 90%= $11,250) = $26,250. $26,250 + $2500 = $28,750 overall in the account after 10 years
Answer:
an=an-1
Step-by-step explanation:
as it doesnt have -6 +3n
I believe the answer is b
