Answer:
I cant see that, its upside down.
Step-by-step explanation:
C
I believe is the right one
Answer:
a = 3 7/18 or 3.388889
Step-by-step explanation:
First, you want to get the a by itself, so you would subtract 4 from the left side of the equals sign.
6a + 4 = 61 / 3 + 4
-4 -4
6a = 61 / 3
By doing that, they cancel each other out, so you are left with
6a = 61 / 3
Then you want to get a by itself, so you divide 6 from both sides.
6a / 6 = 61 / 3 / 6
Remember that 6 can also be written as 6/1
Remember that dividing a fraction is multiplying the reciprocal.
6a / 6 = 61 / 3 / 6 / 1
When dividing fractions remember to Skip the first fraction, Flip the second fraction, and Multiply the two fractions together.
61 / 3 x 1 / 6
skip multiply flip
Multiply across the top, and across the bottom.
61(1) and 3(6)
Then you get
61 / 18
So a = 61 / 18
If you want to convert that to a mixed number, it would be 3 7 / 18
If you want that in a decimal, it would be 3.388889
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Answer:
2
Step-by-step explanation:
