3(2k - 5) = 6(k - 4) + 9
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Since we know that g(x) is between h(x) and f(x) we can use the same formula format.
If g(x) = a * b^x
a = 160 most likely
b^x would be between 4/5 and 1/5
Look at desmos example below where the third is 3/5^x and lies directly between the first 2
If g(x) = a * b^x
a = 160 most likely
b^x would be between 4/5 and 1/5
Look at desmos example below where the third is 3/5^x and lies directly between the first 2
