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3 years ago

Help me with this pls

Mathematics

1 answer:

swat323 years ago

4 0

Answer:

180

Step-by-step explanation:

guessed the answer

that was the easiest

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if the x- and y- values in each pair of a set of ordered pairs are interchanged, the resulting set of ordered pairs is known as

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Alicia says the expression 2(m +4)+5 is equivalent to the expression 2m+13. Identify two properties that can be used to support

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3 years ago

What is the value of the expression “three less than the quotient of ten and a number, increased by six” when n = 2?

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Answer:

Step-by-step explanation:

The given expression is "three less than the quotient of ten and a number, increased by six”

The quotient of ten and a number increased by six is translated into mathematical expression as:

$\frac{10}{n}+6$

Three less than the quotient of ten and a number, increased by six is

$(\frac{10}{n}+6)-3$

When we substitute n=2, we get:

$(\frac{10}{2}+6)-3$

Divide to get:

$(5+6)-3$

Add to get:

$11-3$

Subtract

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3 years ago

Solve the equation or formula for the indicated variable.

alex41 [277]

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The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,

Stella [2.4K]

Answer:

$P_4 = 7604.08$

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

$P_1 = P_0 + 0.04P_0$

Where $P_0$ is the initial population and $P_n$ is the population in year n

In year 2

$P_2 = P_1 + 0.04P_1$

It can also be written as:

$P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)$

Taking out common factor $P_0$

$P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)$

Taking out common factor (1 + 0.04)

$P_2 = (1 + 0.04) (P_0 + 0.04P_0)$

Taking out again common factor $P_0$

$P_2 = (1 + 0.04) (1 + 0.04) P_0$

Simplifying

$P_2 = P_0 (1 + 0.04) ^ 2$

$P_n = P_0 (1 + 0.04) ^ n$

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

$P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08$

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3 years ago