Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
A = 52°, a = 149.2, c = 174.3
Step-by-step explanation:
Technology is useful for this. Many graphing calculators can solve triangles for you. The attachment shows a phone app that does this, too.
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The Law of Sines can give you the value of c, so you can choose the correct answer from those offered.
c = sin(C)·b/sin(B) = sin(113°)·49/sin(15°) ≈ 174.271 ≈ 174.3 . . . . . third choice
Angles 6 and 8 add up to equal 180, so 2x - 5 + x + 5 = 180. 3x = 180 so x = 60. Angle 3 is alternate interior to angle 6 which is 2(60) - 5 = 115, so angle 3 is also 115
Answer:
x = 12
Step-by-step explanation:
Answer:
D. larger than volume.
Step-by-step explanation:
Volume is just the space provided within something, while the mass is the weight of the something being evaluated. The bigger the volume, the larger the mass will be.
