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hoa [83]
2 years ago
6

How many moles of iron metal are required to react completely with 12 moles of oxygen?

Chemistry
2 answers:
AlexFokin [52]2 years ago
6 0

Answer:

16 moles

Explanation:

from the equation:

4Fe + 3O2 -----> Fe2O3

the mole ratio of Fe to O2 follows,

3 moles O2 reacts with 4 moles Fe.

therefore,

1 mole O2 reacts with 4/3 moles Fe

and 12 moles O2 reacts with (4/3) × 12 moles Fe = 16 moles

Sophie [7]2 years ago
6 0

Answer:

9.0 moles of O2 and produce 6.0 moles of Fe2O3

Explanation:

Fe→Fe3++3e− iron. Is oxidised: it's losing electrons

O2+4e−→2O2− oxygen Is reduced, it's gaining electrons

Balance for the electrons.

The smallest common product of 3 and 4 Is 12.

So we get:

4Fe→4Fe3++12e−

3O2+12e−→6O2−

Adding:

4Fe+3O2+12e−→4Fe3++12e−+6O2−

The electrons balance so they cancel out:

4Fe+3O2→4Fe3++6O2−

Since Fe and O can combine in a ratio of 2:3

4Fe+3O2→4Fe3++6O2−→2Fe2O3

Extra :

Pure iron. won't rust, because the oxide layer would form a protective skin (as aluminium does). It needs some impurities (mainly carbon) and, apart from the oxygen, some moisture -- even carbondioxide 'helps'. In that case iron.-hydroxy-oxides and -carbonates are formed, and these flake, no longer protecting the iron. underneath.

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4 0
3 years ago
To determine the concentration of chloride ion (Cl-) in a 100 mL sample of ground water, a chemist adds a large enough volume of
Orlov [11]

Answer:

[Cl^-]=232.3\frac{mgCl^-}{L}

Explanation:

Hello,

In this case, we can represent the chemical reaction as:

Cl^-(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NO_3^-(aq)

In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:

m_{Cl^-}=93.3mgAgCl*\frac{1mmolAgCl}{143.32mgAgCl}*\frac{1mmolCl^-}{1mmolAgCl} *\frac{35.45mgCl^-}{1mmolCl^-} =23.23mgCl^-

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[Cl^-]=232.3\frac{mgCl^-}{L}

Best regards.

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4 years ago
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Answer:

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