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3 years ago

13

for 9x + 25= 88, deena wrote the situation "i bought some shirts at the store for 9$ each and received a 25$ discount. my total

bil was $88. what mistake did deena make

1 answer:

MrRissso [65]3 years ago

3 0

Deena has included the discount on the wrong side of the equation.

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If x is a positive integer, for how many different values of x is sqrt48/x a whole number?

slava [35]

Answer:

<u>The only possible values of x that fulfill with both conditions are 3, 12 and 48.</u>

Step-by-step explanation:

1. What are the positive integers? Also know as the whole numbers or the counting numbers. They start from 1, and continue to 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, etc.

2. What are the whole numbers? The definition of whole numbers is that they are the number with no fractions or decimals.

3. According to those definitions, x must be a positive integer and the result of √48/x, must be a whole number.

4. For fulfilling the first condition, x must be only a value from 1 to 48.

5. For fulfilling the second condition, the result of √48/x must be a whole number. It means it must be 1, 2, 3, 4, 5 or 6. From 7 is not possible to continue because those numbers are bigger than 48, for example √49, √64, √81, √100 and so on, and it would be impossible to fulfill with the first condition.

6. So, we have just 6 possible options (√48/x = 1, √48/x = 2, √48/x = 3, √48/x = 4, √48/x = 5 and √48/x =6). Let's review in detail one by one.

√48/x = 1, Is there any value of x for fulfilling both conditions? <u>Yes, it's. It's 48. </u>

√48/x = 1 and let's replace x by 48.

√48/48 = √1 = 1

√48/x = 2, Is there any value of x for fulfilling both conditions? <u>Yes, it's. It's 12. </u>

√48/x = 2 and let's replace x by 12.

√48/12 = √4 = 2

√48/x = 3, Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √9 = 3

√48/x = 4, Is there any value of x for fulfilling both conditions? <u>Yes, it's. It's 3. </u>

√48/x = 4 and let's replace x by 3.

√48/3 = √16 = 4

√48/x = 5 Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √25 = 5

√48/x =6 Is there any value of x for fulfilling both conditions? No, it isn't.

There isn't any whole number that allow us to fulfill with this: √48/x = √36 = 6.

<u>The only possible values of x that fulfill with both conditions are 3, 12 and 48.</u>

6 0

3 years ago

If f(x) = 7(x - 2) + 4(x + 1), what is f(2)? <br><br>O 9 <br>O 10<br>O 11 <br>O 12

Jlenok [28]

I THINK it’s 11 .........

4 0

3 years ago

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If the two lines below are perpendicular and the slope of the red line is -

yaroslaw [1]

Answer:

-(10/7)

Step-by-step explanation:

See attached graphic. The slope of the Green Line is cut off in the problem photo, but can be calculated from the graph to find the slope of the Red Line. The answer options are on drugs; pick the one that looks closest.

5 0

2 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is<em> </em> $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, <em>the probability that a student has either a Visa card </em><em>or</em><em> a MasterCard is </em> $\\ P(V \cup M) = 0.88$ .<em> </em>

Are the events V and M independent?

A way to solve this question is by using the concept of <em>conditional probabilities</em>.

In Probability, two events are <em>independent</em> when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a <em>conditional probability</em> or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events <em>were independent</em>.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

3 years ago

20. What is the reciprocal of 5 3/4?

pogonyaev

Answer:

hi good morning

Step-by-step explanation:

i think it must be 23/4 or 46/8 etc.

hope it helped

4 0

3 years ago

Read 2 more answers