Question

The rectangle below has an area of 15x^3y^415x 3 y 4 square meters and a length of 3x^2y3x 2 y meters.What is the width of the rectangle?

Answer 1

Answer:

The width of the rectangle is $5xy^3$.

Step-by-step explanation:

The area of a rectangle is the product of length and width of the rectangle.

$A=length\times width$

It is given that the area of the rectangle is $15x^3y^4$ square meters and the length of the rectangle is $3x^2y$.

$15x^3y^4=3x^2y\times width$

$width=\frac{15x^3y^4}{3x^2y}$

$width=\frac{3\times 5\times x^2\times xy^3\times y}{3x^2y}$

Cancel out common factors 3x²y.

$width=5xy^3$

Therefore the width of the rectangle is $5xy^3$.