1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
musickatia [10]
3 years ago
13

What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s

uperscript on circle PPP below?
Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

tankabanditka [31]3 years ago
4 0

Answer:

186 is correct on khan academn=y

You might be interested in
(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each
Leviafan [203]

Following are the solution parts for the given question:

For question A:

\to (n) = 16

\to (\bar{X}) = 410

\to (\sigma) = 40

In the given question, we calculate 90\% of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}

\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\

Using the t table we calculate t_{ \frac{\alpha}{2}} = 1.753  When 90\% of the confidence interval:

\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53

So 90\% confidence interval for the mean weight of shipped homemade candies is between 392.47\ \ and\ \ 427.53.

For question B:

\to (n) = 500

\to (X) = 155

\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31

Here we need to calculate 90\% confidence interval for the true proportion of all college students who own a car which can be calculated as

\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}

\to C.I= 0.90

\to (\alpha) = 0.10

\to \frac{\alpha}{2} = 0.05

Using the Z-table we found Z_{\frac{\alpha}{2}} = 1.645

therefore 90\% the confidence interval for the genuine proportion of college students who possess a car is

\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344

So 90\% the confidence interval for the genuine proportion of college students who possess a car is between 0.28 \ and\ 0.34.

For question C:

  • In question A, We are  90\% certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
  • In question B, We are  90\% positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:  

brainly.in/question/16329412

7 0
3 years ago
Which formula gives the average rate of change of f(x) over the interval [8,12]?
Kruka [31]
I think the answer is C hope this would help you
5 0
3 years ago
Read 2 more answers
Nancy made 3 different stacks of wooden blocks. The first stack was 6 blocks high, the second
tensa zangetsu [6.8K]

Answer:30

Step-by-step explanation:6+9+15=30

6 0
3 years ago
Read 2 more answers
Miles is playing catch with his friend. He throws the baseball from point A to point B
MAXImum [283]

Answer:

1234567890

Step-by-step explanation:

1234567890

8 0
3 years ago
56of the 90pets in the pet show are cats 4/5of the cats are calico cats. What fraction of the pets are calico cats?
meriva
To get the answer, we can divide 56 by 5 to find one fifth of the cats. Then, we can multiply this number to get four fifths of the cats. Then, we put this number over 90 since there is 90 pets in the entire show. Then, this answer ends up being about half all of the pets are calicos.
4 0
3 years ago
Read 2 more answers
Other questions:
  • When Jaylen started high school, 1,430 students attended his school. On the day of his graduation, only 1,001 students attended
    6·2 answers
  • The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
    11·1 answer
  • What is an algebraic expression?
    13·2 answers
  • Lori can do 42 push-ups. This is ten less than twice the amount of push-ups her sister can do. How many push-ups can her sister
    8·2 answers
  • Find the area of the regular polygon.<br> Round to the nearest tenth.
    10·1 answer
  • What is 37.6 ×0.9 +4^5÷16-38%of 25. show work please
    13·2 answers
  • The sale price of an item is Rs 176. If a discount of 20% is allowed on its Marked price, what is the marked price of the item
    7·1 answer
  • If $12.000 is invested in an account in which the interest earned is continuously
    9·1 answer
  • Help i dont know what to do here :|
    9·1 answer
  • If f(x) = 2x - 9, which of the following are correct? Select all that apply. f(-1) = -11 f(2) = 5 f(3) = -3 f(0) = -9 f(-3) = 15
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!