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4 years ago

Help please. The question is...

Mathematics

1 answer:

Doss [256]4 years ago

5 0

Answer:

A (2+3n)÷5

Step-by-step explanation:

Lets break this down into step by step.

1) it says that it is the quotient of two. This means that we are dividing by a number. So the answer has to be dividing. So that means it's A or C

2) it says 2 more than 3 times a number <em>n</em><em>.</em><em> </em>This shows that the 2 is adding to 3 times n. so that canceled out C meaning it's A.

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Help,<br> what do i put in the blanks

Vikki [24]

For saturday’s empty box it’s 35
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4 0

3 years ago

Read 2 more answers

If y=6 When x=10,find x when y=18

erik [133]

X=22 because if y=6 and x=10 so 6+4=10 so 18+4=22

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4 years ago

Can someone help me with this exercise?

olga2289 [7]

Answer:

View image

Step-by-step explanation:

You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.

Your first goal is to solve for y, which I did at the top.

And remember that when you divide/multiply by a negative number you have to flip the inequality sign.

So the first equation is already in term of y. (y < 2x + 4)

So you only have to solve for y for -3x - 2y ≥ 6.

I solved that and got y ≤ -3/2x - 3.

Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3

First you gotta treat it like a normal equation and graph them.

So i graphed y = 2x + 4 and y = -3/2x - 3. I assume you already know how do do that.

btw. < and > have dotted lines, while ≤ and ≥ have solid lines.

Now for the shading, you gotta look at the inequality sign.

y < 2x + 4 has a less than sign, so you have to shade everything underneath the line you graphed.

y ≤ -3/2x - 3 is also less than, so you have to shade everything underneath that line as well.

So in the future, you you get a > or ≥ then you have to shade above the graph.

5 0

3 years ago

Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$