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castortr0y [4]
3 years ago
6

Solve pls brainliest

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

Mixed number: 8.72=8 72/100

Improper fraction: 8.72= 872/100

Step-by-step explanation:

8 is in the ones place, 7 is in the tenths place, and 2 is in the hundreths place, which makes 8.72. In fractions, that would be 8 wholes, and 72/100, which is 8 72/100. After that, you can turn it into an improper fraction by doing 8x100, which is 800, then you add 72, which is 872. That makes 872 the numerator, and 100 the denominator, which makes 872/100.

Btw (I didn't simplify, as the problem states against it!)

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Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let y\in (x-\epsilon,x+\epsilon). then we have that x-\epsilon. Hence, it makes sense to define the positive number delta as \delta=\min\{x+\epsilon-y,y-(x-\epsilon)\} (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon), and if we prove this, we are done. To prove it, let z\in (y-\delta,y+\delta), then y-\delta. First, \delta \leq y-(x-\epsilon) then -\delta \geq -y+x-\epsilon hence z>y-\delta \geq x-\epsilon

On the other hand, \delta \leq x+\epsilon-y then z hence z. Combining the inequalities, we have that  x-\epsilon, therefore (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon) as required.  

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A boat has two sails in the shape of right triangles, labeled A and B in the figure below.
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Step-by-step explanation:

5 0
3 years ago
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Can ya'll help me? tehee :)
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Suppose that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The
Marina86 [1]

Answer:

Step-by-step explanation:

Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.

G = card drawn is green

Y = card drawn is yellow

E = card drawn is even-numbered

List:

Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}

2) P(G) = 5/8

3) P(G/E) = P(GE)/P(E)

GE = {G2, G4}

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6) No there is common element as G2 and G4

Cannot be mutually exclusive

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3 years ago
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