Answer:
37/200
Step-by-step explanation:
Event/Sample Space = .185 = 18.5%
I hope this helps you
volume of sphere =4/3.pi.r^3
Step-by-step explanation:
Given,
length of rectangle(l)= 8cm
area of rectangle(A) = 48cm2
breadth of rectangle(b) = ?
Perimeter of rectangle (P)=?
We know ,
Area of rectangle(A) = l×b
or, 48cm2 = 8cm×b
or, 48cm2 = 8bcm
or, 48cm2/8cm = b
or, 6cm = b
or, b = 6cm
therefore, b = 6cm
Perimeter of rectangle (P) = 2(l+b)
= 2(8cm+6cm)
= 2×14cm
= 28cm
therefore, Perimeter of rectangle(P) = 28cm
Now,
According to the question,
Perimeter of rectangle(P) = Perimeter of square(P)
So,
Perimeter of square(P) = 28cm
length of square(l) = ?
Area of square (A) = ?
We know,
Perimeter of square (P) = 4l
or, 28cm = 4l
or, 28cm/4 = l
or, 7cm = l
or, l = 7cm
therefore, l = 7cm
Now,
Area of square (A) = l^2
= (7cm)^2
= 7cm×7cm
= 49cm^2
therefore, area of square (A)= 49cm^2
Answer:
14 ÷ 9 = 1.55555555556
9 ÷ 14 = 0.64285714285
14 ÷ 5 = 2.8
5 ÷ 14 = 0.35714285714
Step-by-step explanation:
pls mark me brainliest
Answer:
And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:
And the standard error is given by:
We want to construct a 68% confidence interval so then the significance level would be :
and 
. The confidence interval is given by:
Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:
And replacing we got:
And the best option would be:
D. (0.191 to 0.249)
