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Allushta [10]
3 years ago
7

Which value of x satisfies both 3x + y = 9 and 3x − 5y = 15?

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0
*Hint: In order to find the value of x you could solve this equation by the elimination method and eliminate y.

(3x + y = 9)5
3x - 5y = 15

15x + 5y = 45
3x - 5y = 15

18x = 60
x = 10/3

The answer would be A.
Lunna [17]3 years ago
5 0
The answer to the question is A.
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Consider h(x)=x^2+8+15. identify its vertex and y-intercept.
OleMash [197]

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Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, [x = \frac{-b}{2a}, h(\frac{-b}{2a})].

<h3>Use the equation:  [x = \frac{-b}{2a}, h(\frac{-b}{2a})]</h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

x = \frac{-b}{2a}

x = \frac{-8}{2(1)}

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

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h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

5 0
3 years ago
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