The unknown number . . . . . (z)
The sum of the unknown number and 22 . . . . . (z + 22)
The sum of the unknown number and 22
divided by the same unknown number . . . . . . . (z + 22) / z
You said that quotient is 12. (z + 22) / z = 12
Multiply each side by 'z' : (z + 22) = 12 z
Subtract 'z' from each side: 22 = 11 z
Divide each side by 11 : 2 = z .
Answer:
Ainsworth (1970) identified three main attachment styles, secure (type B), insecure avoidant (type A) and insecure ambivalent/resistant (type C).
Step-by-step explanation:
For example, Schaffer and Emerson suggested that attachments develop in four stages: asocial stage or pre-attachment (first few weeks), indiscriminate attachment (approximately 6 weeks to 7 months), specific attachment or discriminate attachment (approximately 7-9 months) and multiple attachment (approximately 10
Answer:
Answer is in the attachment.
Step-by-step explanation:
To graph x>2 consider first x=2. x=2 is a vertical line and if you want to graph x>2 you need to shade to the right of the vertical line.
To graph x+y<2, I will solve for y first.
x+y<2
Subtract x on both sides:
y<-x+2
Consider the equation y=-x+2. This is an equation with y-intercept 2 and slope -1 or -1/1. So the line you have in that picture looks good for y=-x+2. Now going back to consider y<-x+2 means we want to shade below the line because we had y<.
Now where you see both shadings will be intersection of the shadings and will actually by your answer to system of inequalities you have. In my picture it is where you have both blue and pink.
I have a graph in the picture that shows the solution.
Also both of your lines will be solid because your question in the picture shows they both have equal signs along with those inequality signs.
Just in case my one graph was confusing, I put a second attachment with just the solution to the system.
Add the equations.
x-y%2B0.5x%2By=7%2B5
1.5x=12
highlight%28x=8%29
Now use either equation to solve for y.
8-y=7
highlight%28y=1%29
x=8
y=1