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Oliga [24]
4 years ago
14

Which of the following represents a statistical question?

Mathematics
1 answer:
harkovskaia [24]4 years ago
3 0
The third one, because statistical questions have variables that can change
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Express your answer in scientific notation.
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It’s 1.77 times 10to the 6th
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3 years ago
Which statements about the line that passes through (−2, 0) and (2, −4) are true? Select all that apply.
Gennadij [26K]

The statement about the line that passes through (-2, 0) and (2, -4) that are true are:

Option B:The line intersects the y-axis at (0, −2).

Option C: The equation of the line is y = −x − 2.

Option D: The line intersects the x-axis at (−2, 0).

<u>Solution:</u>

Given, two points are (-2, 0) and (2, -4)

We have to select the options that states true about line that passes through given two points.

Now, let us find the line equation that passes through given two points using point slope form.  

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { is a point on the line. }

Now slope "m" is given as:

\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{0-(-4)}{-2-2}=\frac{4}{-4}=-1

Then, line equation = y – 0 = -1(x – (-2))

y = -1(x + 2)

y = -x – 2 --- equation 1

Now let us check options.

<u>Option a)</u> slope of line is 1  

We know that slope of our line is -1 so this option is wrong.

<u>Option b)</u> line intersects y – axis at (0, -2)

When line meets y – axis x becomes 0 ⇒ 0 + y + 2 = 0 ⇒ y = -2  so point is (0, -2).  

This option is right.

<u>Option c) </u>equation of line is y = -x – 2

The given equation is x + y + 2 = 0 ⇒ y = -x – 2 . so this option is correct.

<u>Option d) </u>line intersects at (-2, 0)

When line meets x – axis y becomes 0 ⇒ x + 0 + 2 = 0 ⇒ x = -2. So point is (-2, 0).

This option is right.

Hence, options b, c, d are correct.

8 0
4 years ago
What is rounding for math
Sedaia [141]

Answer:

Step-by-step explanation:

Rounding means making a number simpler but keeping its value close to what it was. The result is less accurate, but easier to use. Example: 73 rounded to the nearest ten is 70, because 73 is closer to 70 than to 80. But 76 goes up to 80. There are many ways to round.

5 0
3 years ago
Read 2 more answers
Need help checking if they are right
Stells [14]

Answer:

Step-by-step explanation:

so I see at the top , it's saying the triangles are "similar" this is a very important part.   meaning that the triangles are copies of each other just bigger or smaller but other wise the same.

QR is 25    check

HG is 30   check

X1 = 48  check

X2 = 14 check

x3 =  6 check

7 0
3 years ago
Read 2 more answers
RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that
schepotkina [342]

Answer:

<u>Question 11:</u>

\angle DAC = 53^\circ

\angle AED = 90^\circ

\angle ADC = 74

DB = 16

AE = 6.03

AC = 12.06

<u>Question 12:</u>

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

<u>Question 11</u>

Given

\angle BAC = 53^\circ

DE = 8

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): \angle DAC

Diagonal CA divides \angle DAB into 2 equal angles

i.e

\angle DAC = \angle BAC

So:

\angle DAC = 53^\circ

Solving (b): \angle AED

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

\angle AED = 90^\circ

Solving (c): \angle ADC

First, we calculate \angle ADE, considering \triangle ADE:

\angle ADE + \angle AED + \angle DAC = 180

\angle ADE + 90 + 53 = 180

\angle ADE + 143 = 180

\angle ADE = -143 + 180

\angle ADE = 37

To calculate \angle ADC, we have:

\angle ADC = 2*\angle ADE

\angle ADC = 2* 37

\angle ADC = 74

Solving (d): DB

From the rhombus

DB = DE +EB

Where

DE =EB

So:

DB = 8 + 8

DB = 16

Solving (e): AE

To do this we consider \triangle ADE

Using the tan formula

tan(\angle ADE) = \frac{AE}{DE}

\angle ADE = 37 and DE = 8

So:

\tan(37) = \frac{AE}{8}

AE = 8 * \tan(37)

AE = 6.03

Solving (f): AC

This is calculated as:

AC = AE + EC

Where

AE = EC

AC = 6.03 +6.03

AC = 12.06

<u>Question 12: Isosceles Triangle</u>

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

4 0
3 years ago
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