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Rainbow [258]
3 years ago
11

Identify the property used in the first four steps to solve the equation 4(x-7)=2x-6

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

x = 11

distributive law

additive law

multiplication property

Step-by-step explanation:

Given in the question an equation

4(x-7) = 2x-6

Distributive law

a(b+c) = ab +ac

4x - 4(7) = 2x - 6

4x -28 = 2x - 6

Use the addition property of equality to reduce the 2x on the right.

4x - 2x - 28 = 2x - 2x -6

4x -2x -28 = -6

Use the addition property of equality to reduce -28 to zero on the left.

4x - 2x- 28 + 28 = -6 + 28

2x = 22

Use the multiplication property of equality to reduce 2x to just x

2x2 = 22/22

x = 22/2

x = 11

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hoa [83]

Given:

The expressions are:

2x(x^2-6x+3)

2a^2(5b^2+3ab+6a+1)

To find:

The product of each expression.

Solution:

According to the distributive property of multiplication over addition, we get

a(b+c)=ab+ac

The first expression is:

2x(x^2-6x+3)

Using distributive property of multiplication over addition, we get

2x(x^2-6x+3)=(2x)(x^2)+(2x)(-6x)+(2x)(3)

2x(x^2-6x+3)=2x^3-12x^2+6x

Therefore, the product of 2x(x^2-6x+3) is 2x^3-12x^2+6x.

The second expression is:

2a^2(5b^2+3ab+6a+1)

Using distributive property of multiplication over addition, we get

2a^2(5b^2+3ab+6a+1)=(2a^2)(5b^2)+(2a^2)(3ab)+(2a^2)(6a)+(2a^2)(1)

2a^2(5b^2+3ab+6a+1)=10a^2b^2+6a^3b+12a^3+2a^2

Therefore, the product of 2a^2(5b^2+3ab+6a+1) is 10a^2b^2+6a^3b+12a^3+2a^2.

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3 years ago
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frutty [35]

Answer:

\boxed{\boxed{\sf x>-7}}

Step-by-step explanation:

\sf -5x-7

Add 7 to both sides:

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Multiply both sides by -1:

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Divide both sides by 5:

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Westkost [7]

Answer:

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The measure of angle B is 37 degrees

Step-by-step explanation:

Here in this question, we are interested in calculating the measure of the two angle.

When how angles are complementary, it means the sum of both equals 90 degrees

mathematically ;

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In order to factor a polynomial, you have to find its roots

x_1,\ x_2,\ldots,x_n

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So, in this case, we're looking for the solutions of

3x^2-25=0 \iff 3x^2=25 \iff x^2 = \dfrac{25}{3} \iff x=\pm\sqrt{\dfrac{25}{3}}=\pm\dfrac{5}{\sqrt{3}}

So, the polynomial can be written as

3x^2-25 = \left(x-\dfrac{5}{\sqrt{3}}\right)\left(x+\dfrac{5}{\sqrt{3}}\right)

5 0
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