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olga55 [171]
3 years ago
10

A TV has a rectangular picture with an area of 6 square feet. The picture has a length of 3 feet. What is the perimeter of

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

Answer:

C. 10 ft.

Step-by-step explanation:

Area of 6 sq. ft. which is rectangular. The length is 3 ft and perimeter is l+l+w+w=perimeter. A rectangular shape has 2 sides of the same length and the other two are the same but, a different length the the other two sides.

Equation:

3+3+2+2=10

kherson [118]3 years ago
5 0
The third one is the answer 10 feet
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Which angles are coterminal with −6π5 ? Select each correct answer. 14π/5 −16π/5 −π/5 −11π/5
wariber [46]
ANSWER

-  \frac{16 \pi}{5}  \: and \:   \frac{14\pi}{5}


EXPLANATION

Coterminal angles are angles in standard position that have the same terminal side.


To find an angle in standard position that is coterminal with

-  \frac{6 \pi}{5}

We add or subtract multiples of
2 \pi

The first addition gives,

-  \frac{6 \pi}{5}  + 2 \pi =  \frac{4 \pi}{5}


We add the second multiple to get,

-  \frac{6 \pi}{5}  +2( 2 \pi )=  \frac{14 \pi}{5}

Since this is the maximum value among the options, we end the addition here.


Let us now subtract the first multiple to get,


-  \frac{6 \pi}{5}  -   2 \pi =   - \frac{16 \pi}{5}


We end the subtraction here because this is the least value among the options.


Therefore the angles that are coterminal with
-  \frac{6 \pi}{5}
are

-  \frac{16 \pi}{5}  \: and \:   \frac{14\pi}{5}


8 0
3 years ago
Read 2 more answers
\The lengths of a lawn mower part are approximately normally distributed with a given mean Mu = 4 in. and standard deviation Sig
chubhunter [2.5K]

Answer:

68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

Step-by-step explanation:

The lengths of a lawn mower part are approximately normally distributed

\mu = 4

Standard deviation =\sigma =0.2

We are supposed to find  What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)

Formula : Z=\frac{x-\mu}{\sigma}

At x = 3.8

Z=\frac{3.8-4}{0.2}

Z=-1

Refer the z table for p value

p value =0.1587

At x =4.2

Z=\frac{4.2-4}{0.2}

Z=1

Refer the z table for p value

p value =0.8413

P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826

So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.

3 0
3 years ago
which answer choice shows both the equation that represents the sentence and the correct solution to that equation?
Serhud [2]

Answer:

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2 years ago
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Sophie [7]

Answer:

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Step-by-step explanation:

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