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vladimir2022 [97]
2 years ago
14

13,22,31,... Find the 31st term. Find the 31st term.

Mathematics
2 answers:
Galina-37 [17]2 years ago
5 0

Answer: 283

Step-by-step explanation:

To do this, it is helpful to get an equation you can use to solve any term.

This equation is:

13 + 9(n-1)

So simply plug in 31 for n to get

13+9(31-1)

=13+270

=283

Ymorist [56]2 years ago
3 0

Answer:

283

Step-by-step explanation:

9x+4=9(31)+4=283

13+9=22

22+9=31

9x

9(1)=9 9+4=13

9x+4

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The table shows the value of an account x years after the account was opened. Based on the exponential regression model, which i
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Answer:

Correct choice is B

Step-by-step explanation:

The exponential regression model can be written as exponential function

y=a\cdot b^x.

Then

5,000=a\cdot b^0=a,\\ \\5,510=a\cdot b^2\Rightarrow 5,510=5,000\cdot b^2,\\ \\b^2=\dfrac{5,510}{5,000}=\dfrac{551}{500}\Rightarrow b\approx 1.05.

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When x=12, you get

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3 years ago
Read 2 more answers
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

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3 years ago
Find the measure of the missing angle. 122,79,90,Z
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The total amount of angles in quadrilateral is 360.so:

z=360-(122+79+90)
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Answer:

Yes

Step-by-step explanation:

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