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gtnhenbr [62]
2 years ago
14

Help pleaseeee!!!!!!!

Mathematics
1 answer:
mylen [45]2 years ago
6 0
Help with what? I need more information
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WILL GIVE BRAINLIEST IF CORRECT! I'm timed plz Help
lesantik [10]

Answer:

C. q Superscript 12

Step-by-step explanation:

q  \: Superscript \:  12 =  {q}^{12} =   { ({q}^{6})}^{2}  \\

4 0
2 years ago
Read 2 more answers
People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear
Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

d.  

α: 0.05

Left critical value: t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306

Right critical value: t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306

e.

t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}

X[bar]= 23

S= 3

t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3

f.

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

7 0
3 years ago
Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?​
kari74 [83]

We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

We know that a geometric sequence is in form a_n=a_1(r)^{n-1}, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

r = Common ratio,

n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

a_n=1\cdot (7)^{n-1}

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where n\geq 1.

4 0
3 years ago
Emily is going to invest in an ascount paying an interest rate of 4.4% compounded
sp2606 [1]
I’m not sure about this one I’m sorry I couldn’t help
3 0
3 years ago
How are the sun rays like mathematical rays
Ludmilka [50]
A ray in mathematics starts at a point and extends infinitely in one direction away from that point
it differes from a line because a line extend indefinitely in both directions

the sun ray starts from the sun and does not pass through the sun so it starts from a point (the sun's surface) and extends indefinitely into space unless it hits something (planets, black holes, endpoint)
4 0
3 years ago
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